(⇒) Assume
T+ is finer than
T−. Now take an
x∈X and
B− containing
x. Then because
B− is open in
T− then it is open in
T+ too, meaning that there exists some basis element
B+ containing
x where
B+⊆B−
(⇐)
Assume: For each
x∈X and each basis element
B−∈B− containing
x, there exists
B+∈B+ such that
x∈B+⊆B−
WTS that
T+ is finer than
T−, i.e. every
set open ala
T− is also open ala
T+.
Take an arbitrary
open set U∈T−. WTS that
U∈T+.
Take an arbitrary
x∈U. Since
U is open, then there is some basis element
B−⊆U containing
x. By assumption, there is a
B+ such that
x∈B+⊆B−. And since
B−⊂U then
B+⊆U.
Thus each
x∈U has a containing
B+⊆U, i.e.,
U is open