Given a set A and element a0∈A, the principal filter with respect to both is the filter
F={S⊆A∣S∋a0}
Given an
ultrafilter U over
A, if
S∈U is
finite, then
U is
principalProof: since
S is
finite, we can write it as
S={s1,s2,…,sk}={s1}∪{s2}∪⋯{sk}. Then by properties of
ultrafilters we know that at
least one of
{s1},{s2},…,{sk} is included in
U and hence
U is
principal.